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#17. Medium-Size Intersection Is Hard To Avoid

Published

18 Nov, 2023

(Back to course page.)

Link to Slides · Link to recording


Prompts for discussion:

  1. Are medium-sized intersections particularly special? Are other-sized intersections also hard to avoid?

  2. Here’s the statement that we used in the next miniature, whose proof is in this one, and one that I chose to skip: Let F\mathcal{F}F be as in the theorem, i.e, ∣F∣≤(n0)+(n1)+⋯+(np−1)|\mathcal{F}| \leq\left(\begin{array}{l} n \\ 0 \end{array}\right)+\left(\begin{array}{l} n \\ 1 \end{array}\right)+\cdots+\left(\begin{array}{c} n \\ p-1 \end{array}\right)∣F∣≤(n0​)+(n1​)+⋯+(np−1​). If n=4pn=4pn=4p, then (4p2p−1)∣F∣≥1.1n. \frac{\left(\begin{array}{c}4 p \\2 p-1\end{array}\right)}{|\mathcal{F}|} \geq 1.1^n \text {. }∣F∣(4p2p−1​)​≥1.1n.  There are (apparently) many ways to prove this. Does this inequality have some visible intuition?


© 2022 • Neeldhara Misra • Credits •

 

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